Nilai \( \displaystyle \lim_{x \to 3} \ \frac{2x^2-4x-6}{x^2-2x-3} = \cdots \)
- -2
- 0
- 2
- 6
- 8
(UN SMA IPS 2017)
Pembahasan:
\begin{aligned} \lim_{x \to 3} \ \frac{2x^2-4x-6}{x^2-2x-3} &= \lim_{x \to 3} \ \frac{2(x^2-2x-3)}{x^2-2x-3} \\[8pt] &= \lim_{x \to 3} \ 2 \\[8pt] &= 2 \end{aligned}
Jawaban C.